[프로그래머스/PYTHON] 옹알이 (2)

https://school.programmers.co.kr/learn/courses/30/lessons/133499

프로그래머스

def solution(babbling):
    answer=0
    li=["aya", "ye", "woo", "ma"]
    for i in babbling:
        word=''
        before_word=''
        for j in i:
            word+=j
            if word in li:
                if before_word != word :
                    before_word=word
                    word=''
        if word=='':
            answer+=1
    return answer